Hexagon Servings Sizes

Decorating By ddaigle Updated 30 Sep 2011 , 1:29pm by ddaigle

ddaigle Posted 29 Sep 2011 , 4:44pm
post #1 of 3

I have seen a 6/9/12/15 (2") Hex cake vary from 137-147 total servings.

I cannot find the total servings for 8/10/12/14 (2") hex cake. Anyone have that total? Thanks

2 replies
jason_kraft Posted 29 Sep 2011 , 4:57pm
post #2 of 3

The area of a hexagon with sides of a certain length is (3 * sqrt(3) / 2) * the length of the side squared. The length of each side is equal to the radius of the hexagon, which is half the diameter. So the surface area of an 8" hexagon is 2.598 * 4^2 = 41.568 sq in.

Assume two layers of cake for each tier and a serving size of 1"x2"x4", so each serving will have a surface area of 2 sq in. 41.568/2 = 20.784 servings for the 8" hex.

The other sizes are below, I used the following Excel formula: =(2.598*(A1/2*A1/2))/2
8  20.784
10  32.475
12  46.764
14  63.651

The total is about 163 servings.

ddaigle Posted 30 Sep 2011 , 1:29pm
post #3 of 3

Thanks Jason!

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